(x+2)^2-4x=8

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Solution for (x+2)^2-4x=8 equation: 



(x+2)^2-4x=8

We move all terms to the left:

(x+2)^2-4x-(8)=0

We add all the numbers together, and all the variables

-4x+(x+2)^2-8=0

We move all terms containing x to the left, all other terms to the right

-4x+(x+2)^2=8

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